Short Overview: Right it's I can bring out of the integral I am then integrating an exponential with respect to time so that would be minus Conclusion to separation of variables solution to 1D transient problem - enforcing non-homogeneous boundary condition.
Me 564 Lecture 16 Part 1 - Overview
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Right it's I can bring out of the integral I am then integrating an exponential with respect to time so that would be minus Conclusion to separation of variables solution to 1D transient problem - enforcing non-homogeneous boundary condition. It's my conduction length and I divided by my cross-sectional area in K and then the resistance to convection is
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- Right it's I can bring out of the integral I am then integrating an exponential with respect to time so that would be minus
- Conclusion to separation of variables solution to 1D transient problem - enforcing non-homogeneous boundary condition.
- It's my conduction length and I divided by my cross-sectional area in K and then the resistance to convection is
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